[第124期]计算年休天数[已结]

nsxlyj

=ROUND(SUM(LOOKUP(MAX(DATEDIF(B2,DATE(YEAR(NOW()),MONTH(B2),DAY(B2)),"m")-1,0)+{0,1},H$3:O$4)*(B2-DATE(YEAR(B2),1,1)-365*{0,1})*{1,-1})/365,)
优化一下
=ROUND(SUM(LOOKUP(MAX((YEAR(NOW())-YEAR(B2))*12-1,0)+{0,1},I$3:P$4)*ABS(B2-DATE(YEAR(B2),1,1)-{0,365}))/365,)
再优化一次,看来还是思路有问题
=ROUND(SUM(LOOKUP(ABS((YEAR(NOW())-YEAR(B2))*12-{1,0}),I$3:P$4)*ABS(B2-DATE(YEAR(B2),1,1)-{0,365}))/365,)
再简化一下
=ROUND(SUM(LOOKUP((YEAR(NOW())-YEAR(B2))*{11.9,12},I$3:P$4)*ABS(B2-DATE(YEAR(B2),1,1)-{0,365}))/365,)

=ROUND(SUM(LOOKUP((YEAR(NOW())-YEAR(B2))/{6.1,6},I$3:P$4/73)*ABS(B2-DATE(YEAR(B2),1,1)-{0,365}))/5,)

goons

公式太长了,凑个数,好久没参与了,数组公式
=ROUND(SUM(ABS({1,0}-DATEDIF(B2-1,EDATE("12-31",0),"YD")/365)*LOOKUP(ABS(DATEDIF(B2,EDATE("12-31",0),"M")-{12,0}),$H$3:$O$3,$H$4:$O$4)),0)


再精简一点
=ROUND(SUM(ABS({0,1}-(TEXT(B2,"m-d")-"1-1")/365)*LOOKUP(ABS(DATEDIF(B2,"12-31","M")-{12,0}),H$3:O$3,H$4:O$4)),0)

titi012

1. =ROUND(SUM(LOOKUP(TEXT(ROW($1:$365)+(YEAR(NOW())&"/1/1")-B2-1,"0;\0")*12/365,I$3:P$4))/365,)

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i5290667

老师不用看这公式了，谢谢！

=IF(IFERROR(MATCH((YEAR(TODAY())-YEAR(B2))*12,$J$3:$Q$3,),),"这个公式超100字符，所以放弃了。这里只为MARK一下！",LOOKUP((YEAR(TODAY())-YEAR(B2))*12,$J$3:$Q$3,$J$4:$Q$4))

=ROUND(DATEDIF(B2,DATE(YEAR(TODAY())+1,1,1),"YD")/365*LOOKUP(DATEDIF(B2,"2018-12-31","M"),$J$3:$Q$3,$J$4:$Q$4),)

太长了，费神！

lijian318

1. =IFERROR(ROUND(SUM(LOOKUP(YEAR(NOW())-YEAR(B2)-{0,1},W$3:AD$3/12,W$4:AD$4)*({1,0}-(B2-(YEAR(B2)&-1))/365*{1,-1})),0),0)

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CLL1998

技术分是拿不了那，哈哈。。。

INT(SUM(LOOKUP(MAX((year(now())-YEAR(B2))*12,1)-{0,1},H$3:O$3,H$4:O$4)*({1,0}-(DATE(year(now()),MONTH(B2),DAY(B2))-DATE(year(now()),1,1))/365)*{1,-1})+0.5)

如果，考虑闰年   
INT(SUM(LOOKUP(MAX((YEAR(NOW())-YEAR(B2))*12,1)-{0,1},H$3:O$3,H$4:O$4)*({1,0}-(DATE(YEAR(NOW()),MONTH(B2),DAY(B2))-DATE(YEAR(NOW()),1,1))/(365+(MOD(YEAR(NOW()),4)=0)))*{1,-1})+0.5)

孤独裘剑

查开始日至本年初月数对应年休天A,至本年末月数对应年休天B，满年日期对应一年中天数C
D2=(C*A+(365-C)*B)/365=B-(B-A)*C/365
=ROUND(LOOKUP(DATEDIF($B2,YEAR(TODAY())&"/12/31","m"),H$3:O$4)-(LOOKUP(DATEDIF($B2,YEAR(TODAY())&"/12/31","m"),H$3:O$4)-LOOKUP(IFERROR(DATEDIF($B2,YEAR(TODAY())&"/1/1","m"),0),H$3:O$4))*DATEDIF(YEAR(TODAY())&"/1/1",DATE(YEAR(TODAY()),MONTH(B2),DAY(B2)),"d")/365,0)，超100了@_@

红旗雪

1. =ROUND(SUM(IFERROR(LOOKUP(DATEDIF(B2,"1-1"+ROW($1:$365)-1,"m"),H$3:O$3,H$4),))/365,)

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七夕、

1. =ROUND(SUM(IFERROR(LOOKUP(DATEDIF(B2,"1-1"+ROW($1:$365)-1,"m"),$3:3,A$4),))/365,)

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再减几个

1. =ROUND(SUM(IFERROR(LOOKUP(DATEDIF(B2,"1-1"+ROW($1:$365)-1,"m"),$3:$4),))/365,)

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xiaoh99

我的公式借用了e2和f2二个单元格，否则公式字符数很难减少。
其中e2单元格录入公式：=HLOOKUP(DATEDIF(B2,DATE(YEAR(NOW()),12,31),"m"),H$3:O$4,2)
f2单元格录入公式：=IF(B2>DATE(YEAR(NOW()),1,1),0,HLOOKUP(DATEDIF(B2,DATE(YEAR(NOW()),1,1),"m"),H$3:O$4,2))
d2单元格中的公式：

=IF(E2=F2,E2,ROUND(E2+(DATE(YEAR(NOW()),1,1)-DATE(YEAR(NOW()),MONTH(B2),DAY(B2)))/365*(E2-F2),0))

共97个字符


多增加一句，我的公式没有错（不知楼主是怎么测试的），看截图：