构造List

luzwales

123-456789 发表于 2020-11-11 15:49
=List.Select(List.TransformMany({1..4},(i)=>{1..4},(x,y)=>{x..y}),each List.Sum(_)>0)

这个简洁，方法比较好

luzwales

练手一下：

1. let
   
2.     myfun = (a,lst)=> List.Transform(
   
3.         {0..(List.Count(lst)-List.PositionOf(lst,a)-1)},each
   
4.         List.Range(lst,List.PositionOf(lst,a),(_+1))),
   
5.     Source = List.Combine(List.Combine(List.Transform({1..4},each myfun(_,{1..4}))))
   
6. in
   
7.     Source
   

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cjh-01

谢谢，辛苦了

deadzlq

(PQ)M Code参考解法

1. let
   
2.   SrcList= {2,3.3,1.5,6},
   
3.   LoopFunc =(pos as number) => List.Generate(()=>[l={SrcList{pos}},i=1],each [i]<=List.Count(SrcList)-pos,each [l=List.Range(SrcList,pos,[i]+1),i=[i]+1],each [l]),
   
4.   Result = List.Combine(List.Transform(List.Positions(SrcList),LoopFunc))
   
5. in
   
6.   Result

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