ExcelHome技术论坛

 找回密码
 免费注册

QQ登录

只需一步,快速开始

快捷登录

搜索
EH技术汇-专业的职场技能充电站 妙哉!函数段子手趣味讲函数 Excel服务器-会Excel,做管理系统 效率神器,一键搞定繁琐工作
HR薪酬管理数字化实战 Excel 2021函数公式学习大典 Excel数据透视表实战秘技 打造核心竞争力的职场宝典
让更多数据处理,一键完成 数据工作者的案头书 免费直播课集锦 ExcelHome出品 - VBA代码宝免费下载
用ChatGPT与VBA一键搞定Excel WPS表格从入门到精通 Excel VBA经典代码实践指南
查看: 1699|回复: 3

[求助] 高手帮忙看下SQL代码运行不了

[复制链接]

TA的精华主题

TA的得分主题

发表于 2010-6-29 20:04 | 显示全部楼层 |阅读模式
drop table #sxy1
drop table #sxy2
drop table #sxy3
drop table #sxy4
drop table #sxy5
drop table #sxy6
drop table #sxy7

select branch,aracde,sum(acctamt_std1+acctamt_std2)/10000 bf into #sxy1 from ipe_cbtg_all where trandate between 20100101 and 20100331 and branch='B0' group by branch,aracde
select branch,aracde,agntnum,sum(acctamt_std1+acctamt_std2) grbf into #sxy2 from ipe_cbtg_all where trandate between 20100101 and 20100131 group by branch,aracde,agntnum having sum(acctamt_std1+acctamt_std2)>=1000 and branch='B0'
select branch,aracde,agntnum,sum(acctamt_std1+acctamt_std2) grbf into #sxy3 from ipe_cbtg_all where trandate between 20100201 and 20100231 group by branch,aracde,agntnum having sum(acctamt_std1+acctamt_std2)>=1000 and branch='B0'
select branch,aracde,agntnum,sum(acctamt_std1+acctamt_std2) grbf into #sxy4 from ipe_cbtg_all where trandate between 20100301 and 20100331 group by branch,aracde,agntnum having sum(acctamt_std1+acctamt_std2)>=1000 and branch='B0'
select branch,aracde,count(agntnum) rs1 into #sxy5 from #sxy2 group by branch,aracde
select branch,aracde,count(agntnum) rs2 into #sxy6 from #sxy3 group by branch,aracde
select branch,aracde,count(agntnum) rs3 into #sxy7 from #sxy4 group by branch,aracde
select a.branch,a.aracde,a.bf,b.rs1,c.rs2,d.rs3 from #sxy1 a
left outer join #sxy5 b on a.aracde=b.aracde
left outer join #sxy6 c on a.aracde=c.aracde
left outer join #sxy7 d on a.aracde=d.aracde
group by a.branch,a.aracde,a.bf,b.rs1,c.rs2,d.rs3
order by a.branch,a.aracde



drop table #sxy1
drop table #sxy2
drop table #sxy3
drop table #sxy4
drop table #sxy5
drop table #sxy6
drop table #sxy7

select branch,partnum,sum(acctamt_std1+acctamt_std2)/10000 bf into #sxy1 from ipe_cbtg_all where trandate between 20100101 and 20100331 and branch='B0' group by branch,partnum
select branch,partnum,agntnum,sum(acctamt_std1+acctamt_std2) grbf into #sxy2 from ipe_cbtg_all where trandate between 20100101 and 20100131 group by branch,partnum,agntnum having sum(acctamt_std1+acctamt_std2)>=1000 and branch='B0'
select branch,partnum,agntnum,sum(acctamt_std1+acctamt_std2) grbf into #sxy3 from ipe_cbtg_all where trandate between 20100201 and 20100231 group by branch,partnum,agntnum having sum(acctamt_std1+acctamt_std2)>=1000 and branch='B0'
select branch,partnum,agntnum,sum(acctamt_std1+acctamt_std2) grbf into #sxy4 from ipe_cbtg_all where trandate between 20100301 and 20100331 group by branch,partnum,agntnum having sum(acctamt_std1+acctamt_std2)>=1000 and branch='B0'
select branch,partnum,count(agntnum) rs1 into #sxy5 from #sxy2 group by branch,partnum
select branch,partnum,count(agntnum) rs2 into #sxy6 from #sxy3 group by branch,partnum
select branch,partnum,count(agntnum) rs3 into #sxy7 from #sxy4 group by branch,partnum
select a.branch,a.partnum,a.bf,b.rs1,c.rs2,d.rs3 from #sxy1 a
left outer join #sxy5 b on a.partnum=b.partnum
left outer join #sxy6 c on a.partnum=c.partnum
left outer join #sxy7 d on a.partnum=d.partnum
group by a.branch,a.partnum,a.bf,b.rs1,c.rs2,d.rs3
order by a.branch,a.partnum



只是将上面一段代码(红色)中的ARACDE替换成PARTNUM,变成第二段代码(紫色)。第二段代码运行错误如下:
服务器: 消息 207,级别 16,状态 3,行 13
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 13
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 14
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 14
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 15
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 15
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 16
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 16
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 16
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 16
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 16
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 16
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 16
Invalid column name 'partnum'.
服务器: 消息 207,级别 16,状态 1,行 16
Invalid column name 'partnum'.

谁帮忙指点下,晕啊

TA的精华主题

TA的得分主题

 楼主| 发表于 2010-6-29 21:44 | 显示全部楼层
表ipe_cbtg_all中肯定有字段 partnum  

TA的精华主题

TA的得分主题

 楼主| 发表于 2010-6-29 21:45 | 显示全部楼层

回复 2楼 zhuhuiling 的帖子

表ipe_cbtg_all中肯定有字段 partnum
您需要登录后才可以回帖 登录 | 免费注册

本版积分规则

手机版|关于我们|联系我们|ExcelHome

GMT+8, 2025-1-12 12:19 , Processed in 0.036897 second(s), 9 queries , Gzip On, MemCache On.

Powered by Discuz! X3.4

© 1999-2023 Wooffice Inc.

沪公网安备 31011702000001号 沪ICP备11019229号-2

本论坛言论纯属发表者个人意见,任何违反国家相关法律的言论,本站将协助国家相关部门追究发言者责任!     本站特聘法律顾问:李志群律师

快速回复 返回顶部 返回列表