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做了个简单的示例,可能有点以偏概全,因为数据数量发生变化,会影响到不同方式的代码效率
贴出来,就是大家讨论下,如何提高此类统计的代码效率
以下三种方式,取决于数据表内,不重复关键字的多少,代码的运行效率就有出入的
具体见附件内容,,,,
Sub 按钮1_Click()
t = Timer
For i = 1 To 100
arr = Sheets(1).UsedRange
Set d = CreateObject("scripting.dictionary")
brr = Sheets(2).UsedRange
For j = 2 To UBound(brr)
If Len(brr(j, 1)) > 0 Then
d(brr(j, 1)) = d(brr(j, 1)) + brr(j, 2)
End If
Next
For j = 2 To UBound(arr)
arr(j, 2) = IIf(d.exists(arr(j, 1)), d(arr(j, 1)), "")
Next j
Sheets(1).UsedRange = arr
Next i
MsgBox Timer - t
End Sub
Sub 按钮2_Click()
t = Timer
For i = 1 To 100
arr = Sheets(1).UsedRange
Set sh = Sheets(1)
Set d = CreateObject("scripting.dictionary")
brr = Sheets(2).UsedRange
For j = 2 To UBound(brr)
If Len(brr(j, 1)) > 0 Then
d(brr(j, 1)) = d(brr(j, 1)) + brr(j, 2)
End If
Next
For j = 0 To d.Count - 1
Set Rng = sh.Columns(1).Find(d.keys()(j), lookat:=xlWhole)
arr(Rng.Row, 2) = d.items()(j)
Next j
Sheets(1).UsedRange = arr
Next i
MsgBox Timer - t
End Sub
Sub 按钮3_Click()
t = Timer
For i = 1 To 100
arr = Sheets(1).UsedRange
Set sh = Sheets(1)
Set d = CreateObject("scripting.dictionary")
brr = Sheets(2).UsedRange
For j = 2 To UBound(brr)
If Len(brr(j, 1)) > 0 Then
d(brr(j, 1)) = d(brr(j, 1)) + brr(j, 2)
End If
Next
For j = 0 To d.Count - 1
sh.Columns(1).Find(d.keys()(j), lookat:=xlWhole).Offset(0, 1) = d.items()(j)
Next j
Next i
MsgBox Timer - t
End Sub
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